问题描述
阅读一些基于范围的循环示例，他们提出了两种主要方法 1，2、3, 4
Reading some examples of range based loops they suggest two main ways 1, 2, 3, 4
std::vector<MyClass> vec;
for (auto &x : vec)
{
// x is a reference to an item of vec
// We can change vec's items by changing x
}
或
for (auto x : vec)
{
// Value of x is copied from an item of vec
// We can not change vec's items by changing x
}
嗯.
当我们不需要更改 vec 项时，IMO、Examples 建议使用第二个版本(按值).为什么他们不建议 const 引用的东西(至少我没有找到任何直接的建议):
When we don't need changing vec items, IMO, Examples suggest to use second version (by value). Why they don't suggest something which const references (At least I have not found any direct suggestion):
for (auto const &x : vec) // <-- see const keyword
{
// x is a reference to an const item of vec
// We can not change vec's items by changing x
}
不是更好吗?当它是一个const 时，它不是避免了每次迭代中的冗余副本吗?
Isn't it better? Doesn't it avoid a redundant copy in each iteration while it's a const?
推荐答案
如果你不想改变项目又想避免复制，那么 auto const & 是正确的选择:
If you don't want to change the items as well as want to avoid making copies, then auto const & is the correct choice:
for (auto const &x : vec)
建议您使用 auto & 的人是错误的.忽略它们.
Whoever suggests you to use auto & is wrong. Ignore them.
这里是回顾:
- 如果要处理副本，请选择
auto x. - 如果您想使用原始项目并可能对其进行修改，请选择
auto &x. - 如果您想使用原始项目而不修改它们，请选择
auto const &x.
这篇关于基于范围的循环:按值获取项目还是对 const 的引用?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！