问题描述
在我的程序中有几次，我不得不检查变量是否是众多选项之一.例如
A few times in my program, I've had to check if a variable was one of many options. For example
if (num = (<1 or 2 or 3>)) { DO STUFF }
我搞砸了OR"，但似乎没有什么是正确的.我试过了
I've messed around with 'OR's, but nothing seems to be right. I've tried
if (num == (1 || 2 || 3))
但它什么都不做.
我想方便地区分几个组.例如
I'd like to conveniently distinguish between several groups. For example
if (num = (1,2,3))
else if (num = (4,5,6))
else if (num = (7,8,9))
推荐答案
如果您要检查的值足够小，您可以创建您要查找的值的位掩码，然后检查要设置的位.
If the values you want to check are sufficiently small, you could create a bit mask of the values that you seek and then check for that bit to be set.
假设您关心几个组.
static const unsigned values_group_1 = (1 << 1) | (1 << 2) | (1 << 3);
static const unsigned values_group_2 = (1 << 4) | (1 << 5) | (1 << 6);
static const unsigned values_group_3 = (1 << 7) | (1 << 8) | (1 << 9);
if ((1 << value_to_check) & values_group_1) {
// You found a match for group 1
}
if ((1 << value_to_check) & values_group_2) {
// You found a match for group 2
}
if ((1 << value_to_check) & values_group_3) {
// You found a match for group 3
}
这种方法最适合不超过您的 CPU 喜欢使用的自然大小的值.在现代，这通常是 64，但可能会因环境的具体情况而异.
This approach works best for values that don't exceed the natural size your CPU likes to work with. This would typically be 64 in modern times, but may vary depending upon the specifics of your environment.
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