本文介绍了捕获“堆栈溢出"递归 C++ 函数中的异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
是否可以在递归 C++ 函数中捕获堆栈溢出异常
?如果是,怎么办?
Is it possible to catch a stack overflow exception
in a recursive C++ function? If so, how?
那么在这种情况下会发生什么
so what will happen in this case
void doWork()
{
try() {
doWork();
}
catch( ... ) {
doWork();
}
}
我不是在寻找特定操作系统的答案.只是一般
I am not looking for an answer to specific OS. Just in general
推荐答案
这本身并不是一个例外,但如果您只想将堆栈使用限制在一个固定的数量,您可以这样做:
It's not an exception per se, but if you just want to be able to limit your stack usage to a fixed amount, you could do something like this:
#include <stdio.h>
// These will be set at the top of main()
static char * _topOfStack;
static int _maxAllowedStackUsage;
int GetCurrentStackSize()
{
char localVar;
int curStackSize = (&localVar)-_topOfStack;
if (curStackSize < 0) curStackSize = -curStackSize; // in case the stack is growing down
return curStackSize;
}
void MyRecursiveFunction()
{
int curStackSize = GetCurrentStackSize();
printf("MyRecursiveFunction: curStackSize=%i
", curStackSize);
if (curStackSize < _maxAllowedStackUsage) MyRecursiveFunction();
else
{
printf(" Can't recurse any more, the stack is too big!
");
}
}
int main(int, char **)
{
char topOfStack;
_topOfStack = &topOfStack;
_maxAllowedStackUsage = 4096; // or whatever amount you feel comfortable allowing
MyRecursiveFunction();
return 0;
}
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