问题描述

我非常有信心全局声明的变量在程序启动时被分配(并初始化，如果适用).

I'm quite confident that globally declared variables get allocated (and initialized, if applicable) at program start time.

int globalgarbage;
unsigned int anumber = 42;

但是在函数中定义的静态函数呢?

But what about static ones defined within a function?

void doSomething()
{
  static bool globalish = true;
  // ...
}

global 的空间是什么时候分配的?我猜程序什么时候开始.但是它也被初始化了吗?还是在第一次调用 doSomething() 时初始化?

When is the space for globalish allocated? I'm guessing when the program starts. But does it get initialized then too? Or is it initialized when doSomething() is first called?

推荐答案

我对这个很好奇所以写了下面的测试程序，并用g++ 4.1.2版本编译.

I was curious about this so I wrote the following test program and compiled it with g++ version 4.1.2.

include <iostream>
#include <string>

using namespace std;

class test
{
public:
        test(const char *name)
                : _name(name)
        {
                cout << _name << " created" << endl;
        }

        ~test()
        {
                cout << _name << " destroyed" << endl;
        }

        string _name;
};

test t("global variable");

void f()
{
        static test t("static variable");

        test t2("Local variable");

        cout << "Function executed" << endl;
}


int main()
{
        test t("local to main");

        cout << "Program start" << endl;

        f();

        cout << "Program end" << endl;
        return 0;
}

结果出乎我的意料.直到第一次调用该函数时，才调用静态对象的构造函数.这是输出:

The results were not what I expected. The constructor for the static object was not called until the first time the function was called. Here is the output:

global variable created
local to main created
Program start
static variable created
Local variable created
Function executed
Local variable destroyed
Program end
local to main destroyed
static variable destroyed
global variable destroyed

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