问题描述
Boost 序列化文档断言序列化/反序列化项目的方法是使用二进制/文本存档，并在底层结构上使用流.如果我不想将序列化数据用作 std::string，这可以正常工作，但我的目的是将其直接转换为 char* 缓冲区.如何在不创建临时字符串的情况下实现此目的?
Boost serialization doc's assert that the way to serialize/deserialize items is using a binary/text archive with a stream on the underlying structure. This works fine if I wan't to use the serialized data as an std::string, but my intention is to convert it directly to a char* buffer. How can I achieve this without creating a temporary string?
解决了！对于那些想要一个例子的人:
Solved! For the ones that wanted a example:
char buffer[4096];
boost::iostreams::basic_array_sink<char> sr(buffer, buffer_size);
boost::iostreams::stream< boost::iostreams::basic_array_sink<char> > source(sr);
boost::archive::binary_oarchive oa(source);
oa << serializable_object;
推荐答案
IIUC，您想写入一个固定大小的预分配数组.
IIUC, you would like to write to a preallocated array of fixed size.
您可以使用 boost::iostreams::array_sink(用 stream 给它一个 std::ostream 接口).
You could use a boost::iostreams::array_sink (wrapped with stream to give it an std::ostream interface) for that.
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