本文介绍了如何将 unique_ptr 捕获到 lambda 表达式中?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！
问题描述
我尝试了以下方法:
std::function<void ()> getAction(std::unique_ptr<MyClass> &&psomething){
//The caller given ownership of psomething
return [psomething](){
psomething->do_some_thing();
//psomething is expected to be released after this point
};
}
但它不编译.有什么想法吗?
But it does not compile. Any ideas?
更新:
建议，需要一些新语法来明确指定我们需要将所有权转移到 lambda，我现在正在考虑以下语法:
AS suggested, some new syntax is required to explicitly specify we need to transfer the ownership to the lambda, I am now thinking about the following syntax:
std::function<void ()> getAction(std::unique_ptr<MyClass> psomething){
//The caller given ownership of psomething
return [auto psomething=move(psomething)](){
psomething->do_some_thing();
//psomething is expected to be released after this point
};
}
它会是一个好的候选人吗?
Would it be a good candidate?
更新 1:
我将展示我对 move 和 copy 的实现如下:
I will show my implementation of move and copy as following:
template<typename T>
T copy(const T &t) {
return t;
}
//process lvalue references
template<typename T>
T move(T &t) {
return std::move(t);
}
class A{/*...*
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