问题描述
这两者有什么区别吗?或者我是否可以安全地在我的代码中用 std::bind
替换每次出现的 boost::bind
,从而消除对 Boost 的依赖?
Is there any difference between the two? Or am I safe to replace every occurrence of boost::bind
by std::bind
in my code and thereby remove the dependence on Boost?
推荐答案
boost::bind
有重载关系运算符,std::bind
没有.boost::bind
支持非默认调用约定,不保证std::bind
(标准库实现可能会将此作为扩展提供).boost::bind
supports non-default calling conventions,std::bind
is not guaranteed to (standard library implementations may offer this as an extension).boost::bind
提供了一种直接机制,允许防止对嵌套绑定表达式(boost::protect
),std::bind
才不是.(也就是说,如果需要,可以将boost::protect
与std::bind
一起使用,或者自己简单地重新实现它.)boost::bind
provides a direct mechanism to allow one to prevent eager evaluation of nested bind expressions (boost::protect
),std::bind
does not. (That said, one can useboost::protect
withstd::bind
if they want, or trivially reimplement it on their own.)std::bind
提供了一种直接机制,允许将任何用户定义的函子视为嵌套的绑定表达式,以便强制急切求值(std::is_bind_expression
: [func.bind.isbind]/1, [func.bind.bind]/10),boost::bind
没有.std::bind
provides a direct mechanism to allow one to treat any user defined functor as a nested bind expression in order to force eager evaluation (std::is_bind_expression
: [func.bind.isbind]/1, [func.bind.bind]/10),boost::bind
does not.这篇关于C++11 std::bind 和 boost::bind 的区别的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!
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