Ok... So I had a silly idea and tried putting the value 0123 into an int, just curious to see what would happen, I assumed that when I printed the value I'd get 123, but instead I got 83... Any ideas why? what happens inside the compiler/memory that makes this value become 83?
我用 GCC 编译器在 C++ 和 C 中尝试过这个，也尝试过使用浮点数产生相同的结果.
I tried this in C++ and C with GCC compiler and also tried with a float which yielded the same results.
推荐答案
在 C/C++ 中，以0"为前缀的数字文字是八进制(基数为 8).
In C/C++ a numeric literal prefixed with a '0' is octal (base 8).
What is inside .lib file of Static library, Statically linked dynamic library and dynamically linked dynamic library?(静态库、静态链接动态库和动态链接动态库的 .lib 文件里面是什么?)
