问题描述
我需要逐行拆分字符串.我以前是这样做的:
I need to split string by line. I used to do in the following way:
int doSegment(char *sentence, int segNum)
{
assert(pSegmenter != NULL);
Logger &log = Logger::getLogger();
char delims[] = "
";
char *line = NULL;
if (sentence != NULL)
{
line = strtok(sentence, delims);
while(line != NULL)
{
cout << line << endl;
line = strtok(NULL, delims);
}
}
else
{
log.error("....");
}
return 0;
}
我输入我们是一体的.不，我们是."并调用 doSegment 方法.但是当我调试时，我发现句子参数是we are one.\nyes we are"，并且拆分失败.有人可以告诉我为什么会发生这种情况，我应该怎么做.无论如何，我还可以使用其他方法在 C++ 中拆分字符串.谢谢！
I input "we are one. yes we are." and invoke the doSegment method. But when i debugging, i found the sentence parameter is "we are one.\nyes we are", and the split failed. Can somebody tell me why this happened and what should i do. Is there anyway else i can use to split string in C++. thanks !
推荐答案
我想使用 std::getline 或 std::string::find 来遍历字符串.下面的代码演示了 getline 函数
I'd like to use std::getline or std::string::find to go through the string. below code demonstrates getline function
int doSegment(char *sentence)
{
std::stringstream ss(sentence);
std::string to;
if (sentence != NULL)
{
while(std::getline(ss,to,'
')){
cout << to <<endl;
}
}
return 0;
}
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