问题描述
我将 CMake 用于一个有两个版本的项目,其中一个需要 -lglapi,另一个不需要.
I'm using CMake for a project that comes in two versions, one of which requires -lglapi and the other does not.
到目前为止,我们使用的行看起来像这样:
So far the lines we used look like that:
SET(CMAKE_C_FLAGS "-O3 -xSSE3 -restrict -lpthread -lX11 -ldrm")
SET(CMAKE_CXX_FLAGS "-O3 -xSSE3 -restrict -lpthread -lX11 -ldrm")
我在 CMakeList.txt 的这些行之后添加了一个 if 语句:
I added an if statement in my CMakeList.txt exactly after those lines:
if(SINGLE_MODE)
SET(CMAKE_C_FLAGS ${CMAKE_C_FLAGS} " -lglapi")
SET(CMAKE_CXX_FLAGS ${CMAKE_CXX_FLAGS} " -lglapi")
endif(SINGLE_MODE)
SINGLE_MODE 变量的定义稍微高一些.当我使用 message 命令显示标志变量的内容时,它看起来没问题:
The SINGLE_MODE variable is defined a little up. When I use the message command to display the content of the flag variables it looks alright:
-O3 -xSSE3 -restrict -lpthread -lX11 -ldrm -lglapi
但是当我开始编译时,我遇到了编译错误.使用详细模式我意识到在编译器调用中它看起来像这样:
But when I start compiling I am running into a compile error. Using the verbose mode I realized that in the compiler call it looks like that:
-O3 -xSSE3 -restrict -lpthread -lX11 -ldrm; -lglapi
即在将 -lglapi 添加到列表之前,以某种方式添加了分号.
I.e. somehow a semicolon got added before adding the -lglapi to the list.
这里有没有人遇到过类似的问题并且知道解决这个问题的方法?我已经用谷歌搜索了一段时间并研究了 CMake 手册,但看不到我在这里做错了什么.
Did anyone here encounter a similar issue and knows a way to fix this issue? I've googled quite a while and studied the CMake manual but couldn't see what I did wrong here.
谢谢,托比亚斯
推荐答案
尝试这样做:
if(SINGLE_MODE)
SET(CMAKE_C_FLAGS "${CMAKE_C_FLAGS} -lglapi")
SET(CMAKE_CXX_FLAGS "${CMAKE_CXX_FLAGS} -lglapi")
endif(SINGLE_MODE)
然后,您确定将 -lglapi
附加到现有的 ${CMAKE_CXX_FLAGS}
字符串.否则,看起来像是正在创建 CMake 列表.
Then, you are sure you append -lglapi
to the existing ${CMAKE_CXX_FLAGS}
string. Else, looks like something like a CMake list is being created.
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