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问题描述
例如这些变量:
result (double)
a (double)
b (float)
c (float)
d (double)
一个简单的计算:
result = a * (b + c) * d
类型转换的方式和时间,以及如何确定每次计算的精度是多少?
How and when are the types converted and how do I figure out what precision each calculation is performed at?
推荐答案
所有操作都在相同类型的对象上完成(假设正常算术运算).
All operations are done on objects of the same type (assuming normal arithmetic operations).
如果你编写的程序使用不同的类型,那么编译器会自动升级ONE参数,使它们都相同.
If you write a program that uses different types then the compiler will auto upgrade ONE parameter so that they are both the same.
在这种情况下,浮动将升级为双打:
In this situations floats will be upgraded to doubles:
result = a * (b + c) * d
float tmp1 = b + c; // Plus operation done on floats.
// So the result is a float
double tmp2 = a * (double)tmp1; // Multiplication done on double (as `a` is double)
// so tmp1 will be up converted to a double.
double tmp3 = tmp2 * d; // Multiplication done on doubles.
// So result is a double
result = tmp3; // No conversion as tmp3 is same type as result.
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