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      1. 如果在从头到尾迭代时在 map 元素上调用 erase() 会发生什么?

        What happens if you call erase() on a map element while iterating from begin to end?(如果在从头到尾迭代时在 map 元素上调用 erase() 会发生什么?)

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                  本文介绍了如果在从头到尾迭代时在 map 元素上调用 erase() 会发生什么?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  在下面的代码中,我遍历地图并测试是否需要删除元素.擦除元素并继续迭代是否安全,或者我是否需要在另一个容器中收集密钥并执行第二个循环来调用 erase()?

                  In the following code I loop through a map and test if an element needs to be erased. Is it safe to erase the element and keep iterating or do I need to collect the keys in another container and do a second loop to call the erase()?

                  map<string, SerialdMsg::SerialFunction_t>::iterator pm_it;
                  for (pm_it = port_map.begin(); pm_it != port_map.end(); pm_it++)
                  {
                      if (pm_it->second == delete_this_id) {
                          port_map.erase(pm_it->first);
                      }
                  }
                  

                  更新:当然,然后我阅读这个问题,但我没有认为会相关,但回答了我的问题.

                  UPDATE: Of course, I then read this question which I didn't think would be related but answers my question.

                  推荐答案

                  C++11

                  这已在 C++11 中得到修复(或擦除已在所有容器类型中得到改进/保持一致).
                  擦除方法现在返回下一个迭代器.

                  C++11

                  This has been fixed in C++11 (or erase has been improved/made consistent across all container types).
                  The erase method now returns the next iterator.

                  auto pm_it = port_map.begin();
                  while(pm_it != port_map.end())
                  {
                      if (pm_it->second == delete_this_id)
                      {
                          pm_it = port_map.erase(pm_it);
                      }
                      else
                      {
                          ++pm_it;
                      }
                  }
                  

                  C++03

                  擦除地图中的元素不会使任何迭代器失效.
                  (除了被删除元素的迭代器)

                  C++03

                  Erasing elements in a map does not invalidate any iterators.
                  (apart from iterators on the element that was deleted)

                  实际上插入或删除不会使任何迭代器失效:

                  Actually inserting or deleting does not invalidate any of the iterators:

                  另见这个答案:
                  马克勒索技术

                  但您确实需要更新您的代码:
                  在您的代码中,您在调用擦除后增加 pm_it.此时为时已晚,已经失效.

                  But you do need to update your code:
                  In your code you increment pm_it after calling erase. At this point it is too late and is already invalidated.

                  map<string, SerialdMsg::SerialFunction_t>::iterator pm_it = port_map.begin();
                  while(pm_it != port_map.end())
                  {
                      if (pm_it->second == delete_this_id)
                      {
                          port_map.erase(pm_it++);  // Use iterator.
                                                    // Note the post increment.
                                                    // Increments the iterator but returns the
                                                    // original value for use by erase 
                      }
                      else
                      {
                          ++pm_it;           // Can use pre-increment in this case
                                             // To make sure you have the efficient version
                      }
                  }
                  

                  这篇关于如果在从头到尾迭代时在 map 元素上调用 erase() 会发生什么?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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