本文介绍了不区分大小写的 std::string.find()的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
I am using std::string
's find()
method to test if a string is a substring of another. Now I need case insensitive version of the same thing. For string comparison I can always turn to stricmp()
but there doesn't seem to be a stristr()
.
I have found various answers and most suggest using Boost
which is not an option in my case. Additionally, I need to support std::wstring
/wchar_t
. Any ideas?
解决方案
You could use std::search
with a custom predicate.
#include <locale>
#include <iostream>
#include <algorithm>
using namespace std;
// templated version of my_equal so it could work with both char and wchar_t
template<typename charT>
struct my_equal {
my_equal( const std::locale& loc ) : loc_(loc) {}
bool operator()(charT ch1, charT ch2) {
return std::toupper(ch1, loc_) == std::toupper(ch2, loc_);
}
private:
const std::locale& loc_;
};
// find substring (case insensitive)
template<typename T>
int ci_find_substr( const T& str1, const T& str2, const std::locale& loc = std::locale() )
{
typename T::const_iterator it = std::search( str1.begin(), str1.end(),
str2.begin(), str2.end(), my_equal<typename T::value_type>(loc) );
if ( it != str1.end() ) return it - str1.begin();
else return -1; // not found
}
int main(int arc, char *argv[])
{
// string test
std::string str1 = "FIRST HELLO";
std::string str2 = "hello";
int f1 = ci_find_substr( str1, str2 );
// wstring test
std::wstring wstr1 = L"ОПЯТЬ ПРИВЕТ";
std::wstring wstr2 = L"привет";
int f2 = ci_find_substr( wstr1, wstr2 );
return 0;
}
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