问题描述
我的代码如下所示:
static int myfunc(const string& stringInput)
{
string word;
stringstream ss;
ss << stringInput;
while(ss >> word)
{
++counters[word];
}
...
}
这里的目的是获取一个输入字符串(用空格''分隔)到字符串变量word中，但是这里的代码好像开销很大——转换输入字符串到字符串流并从字符串流中读取到目标字符串中.
The purpose here is to get an input string (separated by white space ' ') into the string variable word, but the code here seems to have a lot of overhead -- convert the input string to a string stream and read from the string stream into the target string.
有没有更优雅的方式来实现同样的目的?
Is there a more elegant way to accomplish the same purpose?
推荐答案
您问的是如何拆分字符串.Boost 有一个有用的工具 boost::split()
You are asking how to split a string. Boost has a helpful utility boost::split()
http://www.boost.org/doc/libs/1_48_0/doc/html/string_algo/usage.html#id3115768
这是一个将结果词放入向量的示例:
Here's an example that puts the resulting words into a vector:
#include <boost/algorithm/string.hpp>
std::vector<std::string> strs;
boost::split(strs, "string to split", boost::is_any_of(" "));
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