问题描述
给定一个容器来获取相关的迭代器很容易，例如:
It is easy given a container to get the associated iterators, example:
std::vector<double>::iterator i; //An iterator to a std::vector<double>
我想知道是否有可能，给定一个迭代器类型，推导出对应容器"的类型(这里我假设每个容器只有一个(非常量)迭代器).
I was wondering if it is possible, given an iterator type, to deduce the type of the "corresponding container" (here I am assuming that for each container there is one and only one (non-const) iterator).
更准确地说，我想要一个适用于所有 STL 容器的模板元函数(无需为每个容器手动专门化它)，例如:
More precisely, I would like a template metafunction that works with all STL containers (without having to specialize it manually for each single container) such that, for example:
ContainerOf< std::vector<double>::iterator >::type
评估为
std::vector<double>
有可能吗?如果没有，为什么?
Is it possible? If not, why?
在此先感谢您的帮助！
推荐答案
我认为这不可能.在某些 STL 库中，您实际上有一个向量迭代器作为指针类型，即std::vector<T>::iterator 是一个 T* 所以我想不出有什么方法可以让你从那里回到容器类型.
I don't think this would be possible. On some STL libraries you actually have a vector iterator as a pointer type, i.e. std::vector<T>::iterator is a T* so I can't think of any way you could get back to the container type from that.
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