本文介绍了将长二进制字符串转换为十六进制c#的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！
问题描述
我正在寻找一种将长二进制字符串转换为十六进制字符串的方法.
I'm looking for a way to convert a long string of binary to a hex string.
二进制字符串看起来像这样 "0110011010010111001001110101011100110100001101101000011001010110001101101011"
the binary string looks something like this "0110011010010111001001110101011100110100001101101000011001010110001101101011"
我尝试过使用
hex = String.Format("{0:X2}", Convert.ToUInt64(hex, 2));
但这只有在二进制字符串适合 Uint64 时才有效，如果字符串足够长则不会.
but that only works if the binary string fits into a Uint64 which if the string is long enough it won't.
还有其他方法可以将二进制字符串转换为十六进制吗?
is there another way to convert a string of binary into hex?
谢谢
推荐答案
我刚刚把这个搞砸了.或许你可以以此为起点……
I just knocked this up. Maybe you can use as a starting point...
public static string BinaryStringToHexString(string binary)
{
if (string.IsNullOrEmpty(binary))
return binary;
StringBuilder result = new StringBuilder(binary.Length / 8 + 1);
// TODO: check all 1's or 0's... throw otherwise
int mod4Len = binary.Length % 8;
if (mod4Len != 0)
{
// pad to length multiple of 8
binary = binary.PadLeft(((binary.Length / 8) + 1) * 8, '0');
}
for (int i = 0; i < binary.Length; i += 8)
{
string eightBits = binary.Substring(i, 8);
result.AppendFormat("{0:X2}", Convert.ToByte(eightBits, 2));
}
return result.ToString();
}
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