本文介绍了在查询中使用 except 时出错的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
此查询有效:
mysql> SELECT s.sno FROM students s;
+------+
| sno |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
| 5 |
| 6 |
| 7 |
| 8 |
| 9 |
| 10 |
+------+
10 rows in set (0.00 sec)
这个查询也有效:
mysql> SELECT t.sno FROM take t WHERE t.cno = 'CS112';
+------+
| sno |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
+------+
4 rows in set (0.00 sec)
但是这个查询:
SELECT s.sno FROM students s
EXCEPT
SELECT t.sno FROM take t WHERE t.cno = 'CS112';
因错误而失败:
mysql> SELECT s.sno FROM students s
-> EXCEPT
-> SELECT t.sno FROM take t WHERE t.cno = 'CS112';
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use n
ear 'EXCEPT
SELECT t.sno FROM take t WHERE t.cno = 'CS112'' at line 2
我在这里做错了什么?
推荐答案
我不相信 MySQL 支持 EXCEPT 语法.尝试使用 NOT IN
或 LEFT JOIN
:
I don't believe MySQL supports EXCEPT syntax. Try using NOT IN
or a LEFT JOIN
:
SELECT s.sno
FROM students s
WHERE s.sno NOT IN
(
SELECT t.sno
FROM take t
WHERE t.cno = 'CS112'
);
或
SELECT s.sno
FROM students s
LEFT JOIN take t ON s.sno = t.sno
WHERE IFNULL(t.cno, '') != 'CS112'
更新
我模拟了你的数据,它正确地返回了 5 到 10:
I mocked up your data as such and it correctly returns 5 through 10:
create temporary table temp_students (sno int)
insert into temp_students values (1)
insert into temp_students values (2)
insert into temp_students values (3)
insert into temp_students values (4)
insert into temp_students values (5)
insert into temp_students values (6)
insert into temp_students values (7)
insert into temp_students values (8)
insert into temp_students values (9)
insert into temp_students values (10)
create temporary table temp_take (sno int, cno varchar(50))
insert into temp_take values (1, 'CS112')
insert into temp_take values (2, 'CS112')
insert into temp_take values (3, 'CS112')
insert into temp_take values (4, 'CS112')
SELECT s.sno
FROM temp_students s
LEFT JOIN temp_take t ON s.sno = t.sno
WHERE IFNULL(t.cno, '') != 'CS112'
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