问题描述
我正在尝试计算一个人在数据库中的年龄.
让我们假设有这个简单的表:
student(id,birth_date);其中 id 是主键(确实该表更复杂，但我已将其简化).
我想知道一个人的年龄:
select id, datediff(curdate(),birth_date)来自学生但它以天为单位返回结果，而不是以年为单位.我可以将其除以 365:
select id, datediff(curdate(),birth_date)/365来自学生但它返回一个浮点值，我想要一个整数.
所以我可以计算年份:
select id, year(curdate())-year(birth_date)来自学生但是有一个问题:比如现在是五月，如果一个人战争出生于1970年六月，他还有31岁而不是32岁，但表达式返回32.
我无法解决这个问题，有人可以帮助我吗?
对于遇到此问题的任何人:
另一种方法是:
SELECT TIMESTAMPDIFF(YEAR, date_of_birth, CURDATE()) 作为学生的差异对于月份的差异，将YEAR替换为MONTH，对于天数，将YEAR替换为DAY
希望有帮助！
I am trying to calculate how old is a person in a database.
Let's suppose to have this simple table:
student(id, birth_date);
Where id is the primary key (truly the table is more complex but I have simplified it).
I want to get how much old is a single person:
select id, datediff(curdate(),birth_date)
from student
But it returns a result in days, and not in years.I could divide it by 365:
select id, datediff(curdate(),birth_date) / 365
from student
But it returns a floating point value, and I want an integer.
So I could calculate the years:
select id, year(curdate())-year(birth_date)
from student
But there is a problem: for instance now is May, if a person war born in June, 1970 he has still 31 years and not 32, but the expression returns 32.
I can't come out of this problem, can someone help me?
For anyone who comes across this:
another way this can be done is:
SELECT TIMESTAMPDIFF(YEAR, date_of_birth, CURDATE()) AS difference FROM student
For differences in months, replace YEAR with MONTH, and for days replace YEAR with DAY
Hope that helps!
这篇关于以整数形式获取 MySQL 中两个日期之间的年差的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！