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        使用 SQL 检测连续的日期范围

        Detect consecutive dates ranges using SQL(使用 SQL 检测连续的日期范围)

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                  本文介绍了使用 SQL 检测连续的日期范围的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我想填充需要开始和结束日期信息的日历对象.我有一个包含日期序列的列.有些日期是连续的(有一天的差异),有些则不是.

                  I want to fill the calendar object which requires start and end date information. I have one column which contains a sequence of dates. Some of the dates are consecutive (have one day difference) and some are not.

                  InfoDate  
                  
                  2013-12-04  consecutive date [StartDate]
                  2013-12-05  consecutive date
                  2013-12-06  consecutive date [EndDate]
                  
                  2013-12-09                   [startDate]
                  2013-12-10                   [EndDate]
                  
                  2014-01-01                   [startDate]
                  2014-01-02 
                  2014-01-03                   [EndDate]
                  
                  2014-01-06                   [startDate]
                  2014-01-07                   [EndDate]
                  
                  2014-01-29                   [startDate]
                  2014-01-30 
                  2014-01-31                   [EndDate]
                  
                  2014-02-03                   [startDate]
                  2014-02-04                   [EndDate]
                  

                  我想选择每个连续日期范围的开始和结束日期(块中的第一个和最后一个).

                  I want to pick each consecutive dates range’s start and end date (the first one and the last one in the block).

                  StartDate     EndDate
                  
                  2013-12-04    2013-12-06
                  2013-12-09    2013-12-10
                  2014-01-01    2014-01-03
                  2014-01-06    2014-01-07
                  2014-01-29    2014-01-31
                  2014-02-03    2014-02-04
                  

                  我只想用 SQL 解决问题.

                  I want to solve the problem using SQL only.

                  推荐答案

                  不需要连接或递归 CTE.标准的间隙和岛解决方案是按(值减去 row_number)分组,因为它在连续序列中是不变的.开始和结束日期只是组的 MIN() 和 MAX().

                  No joins or recursive CTEs needed. The standard gaps-and-island solution is to group by (value minus row_number), since that is invariant within a consecutive sequence. The start and end dates are just the MIN() and MAX() of the group.

                  WITH t AS (
                    SELECT InfoDate d,ROW_NUMBER() OVER(ORDER BY InfoDate) i
                    FROM @d
                    GROUP BY InfoDate
                  )
                  SELECT MIN(d),MAX(d)
                  FROM t
                  GROUP BY DATEDIFF(day,i,d)
                  

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