问题描述
我在一个表中有一个树结构.该表是可以无限嵌套的类别树.每个类别都有一个 ProductCount 列，用于说明该类别中直接包含的产品数量(不汇总子类别).
I have a tree struture in a single table. The table is a tree of categories that can be nested endlessly. Each category has a ProductCount column that tells how many products are directly in the category (not summing child categories).
Id | ParentId | Name | ProductCount
------------------------------------
1 | -1 | Cars | 0
2 | -1 | Bikes | 1
3 | 1 | Ford | 10
4 | 3 | Mustang | 7
5 | 3 | Focus | 4
我想做一个 sql 查询，为每一行/类别提供产品数量，包括子类别中的产品.
I would like to make a sql query that for each row/category gives me the number of products including the ones in the child categories.
上表的输出应该是
Id | ParentId | Name | ProductCount | ProductCountIncludingChildren
--------------------------------------------------------------------------
1 | -1 | Cars | 0 | 21
2 | -1 | Bikes | 1 | 1
3 | 1 | Ford | 10 | 21
4 | 3 | Mustang | 7 | 7
5 | 3 | Focus | 4 | 4
我知道我可能应该使用 CTE，但不能让它以应有的方式工作.
I know I probably should use CTE, but cant quite get it working the way it should.
感谢任何帮助！
推荐答案
你可以使用递归 CTE，在锚部分获取所有行，在递归部分连接获取子行.记住来自锚部分的原始 Id 别名 RootID 并在按 RootID 分组的主查询中做 sum 聚合.
You can use a recursive CTE where you in the anchor part get all rows and in the recursive part join to get the child rows. Remember the original Id aliased RootID from the anchor part and do sum aggregate in the main query grouped by RootID.
SQL 小提琴
MS SQL Server 2012 架构设置:
create table T
(
Id int primary key,
ParentId int,
Name varchar(10),
ProductCount int
);
insert into T values
(1, -1, 'Cars', 0),
(2, -1, 'Bikes', 1),
(3, 1, 'Ford', 10),
(4, 3, 'Mustang', 7),
(5, 3, 'Focus', 4);
create index IX_T_ParentID on T(ParentID) include(ProductCount, Id);
查询 1:
with C as
(
select T.Id,
T.ProductCount,
T.Id as RootID
from T
union all
select T.Id,
T.ProductCount,
C.RootID
from T
inner join C
on T.ParentId = C.Id
)
select T.Id,
T.ParentId,
T.Name,
T.ProductCount,
S.ProductCountIncludingChildren
from T
inner join (
select RootID,
sum(ProductCount) as ProductCountIncludingChildren
from C
group by RootID
) as S
on T.Id = S.RootID
order by T.Id
option (maxrecursion 0)
结果:
| ID | PARENTID | NAME | PRODUCTCOUNT | PRODUCTCOUNTINCLUDINGCHILDREN |
|----|----------|---------|--------------|-------------------------------|
| 1 | -1 | Cars | 0 | 21 |
| 2 | -1 | Bikes | 1 | 1 |
| 3 | 1 | Ford | 10 | 21 |
| 4 | 3 | Mustang | 7 | 7 |
| 5 | 3 | Focus | 4 | 4 |
这篇关于树结构中的递归求和的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！