问题描述
我尝试在 SQL Developer 中运行以下查询，但收到错误消息.我试图声明两个局部变量(var_num1 和 payDate)，然后设置变量.有谁知道我可能做错了什么?我知道 Oracle SQL 与 SQL Server 略有不同.
I am trying to run the following query in SQL Developer, but I am receiving an error. I am trying to declare two local variables (var_num1 and payDate) and then set the variables. Does anyone know what I can be doing incorrectly? I know Oracle SQL is a little different than SQL Server.
DECLARE
var_num1 number;
payDate date;
BEGIN
var_num1 := 100;
payDate := '10/1/2013'
BEGIN
SELECT * FROM Paycode WHERE PaycodeID = var_num1 and PaycodeDate = payDate;
End;
END;
<小时>
Error report:
ORA-06550: line 6, column 2:
PLS-00428: an INTO clause is expected in this SELECT statement
06550. 00000 - "line %s, column %s:
%s"
*Cause: Usually a PL/SQL compilation error.
*Action:
推荐答案
在 PL/SQL 中不能使用没有 INTO 子句的 SELECT.SELECT 的输出必须存储在某处.例如.表或变量或记录.请参阅下面的示例如何将 SELECT 语句的结果存储到记录中.
You cannot use SELECT without INTO clause in PL/SQL. The output of the SELECT must be stored somewhere. Eg. table or variable or perhaps a record. See example below how to store result of the SELECT statement into record.
DECLARE
var_num1 number;
payDate date;
v_result Paycode%ROWTYPE;
BEGIN
var_num1 := 100;
payDate := '10/1/2013';
SELECT * INTO v_result
FROM Paycode
WHERE PaycodeID = var_num1 and PaycodeDate = payDate;
END;
这篇关于Oracle PL/SQL select into 变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！