本文介绍了带有 mysql 变量的 Mysql 查询在 Zend Framework 1 中不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
Zend 配置是:resources.db.adapter = "pdo_mysql"
Zend config is : resources.db.adapter = "pdo_mysql"
得到Message: SQLSTATE[HY000]: General error
$db = Zend_Db_Table::getDefaultAdapter();
$db->setFetchMode(Zend_Db::FETCH_ASSOC);
$qry = $db->fetchAll(" SET @rank = 0 ;
SELECT
@rank := @rank +1 AS rank,
SUM(user_scoring_data.user_points) AS user_points,
league_team.user_id
FROM league_team
RIGHT JOIN user_scoring_data ON league_team.league_team_id = user_scoring_data.league_team_id
WHERE league_id = '$league_id' GROUP BY user_scoring_data.league_team_id
ORDER BY user_points DESC"
);
如果我删除 mysql 变量,它会起作用:
if I remove the mysql variable, it works:
$db->fetchAll("
SELECT
SUM(user_scoring_data.user_points) AS user_points,
league_team.user_id
FROM league_team
RIGHT JOIN user_scoring_data ON league_team.league_team_id = user_scoring_data.league_team_id
WHERE league_id = '$league_id' GROUP BY user_scoring_data.league_team_id
ORDER BY user_points DESC"
);
*注:查询直接在phpmyadmin中测试过,没有错误.
*Note: query was tested directly in phpmyadmin and has no errors.
推荐答案
在 MySql 中设置变量似乎被认为是一个单独的查询.( fetch*() 不能处理多个调用)
It seems setting a variable in MySql is considered a separate query. ( fetch*() cannot handle multiple calls)
所以对于那些有这种问题的人:
so for those with this kind of issue:
$db->query("SET @rank = 0 ;");
$db->fetchAll("SELECT
@rank := @rank +1 AS rank,
SUM(user_scoring_data.user_points) AS user_points,
league_team.user_id
FROM league_team
RIGHT JOIN user_scoring_data ON league_team.league_team_id = user_scoring_data.league_team_id
WHERE league_id = '$league_id' GROUP BY user_scoring_data.league_team_id
ORDER BY user_points DESC"
);
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