问题描述
如果没有线程在等待,使用 Object.wait()
,任何对 Object.notify()
或 Object.notifyAll() 的调用
无效.我有一个场景,如果我在等待集为空时调用 Object.notify()
,随后对 Object.wait()
的调用不应将线程置于等待.如何实现?信号量可能是我能想到的一种解决方案.有没有更优雅的解决方案?
If there is no thread which is waiting, using Object.wait()
, any calls to Object.notify()
or Object.notifyAll()
have no effect. I have a scenario in which if I call Object.notify()
when the wait set is empty, a subsequent call to Object.wait()
should not put the thread to wait. How can this be accomplished? Semaphores may be one solution I can think of. Is there a more elegant solution?
推荐答案
这种场景似乎非常适合 Semaphore
.调用 Semaphore.release()
而不是 notify()
和 Semaphore.acquire()
而不是等待.
This kind of scenario seems to be a perfect fit for a Semaphore
. Call Semaphore.release()
instead of notify()
and Semaphore.acquire()
instead of wait.
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