问题描述
有没有办法将通过计算两个日期之间的差异来计算的天数组织到不同的部分中,例如对于 364 天,它将是:0 年、11 个月、30 天、小时、分钟等.我认为使用逻辑运算符可能像 % 和/一样工作,但由于不同的月份有不同的天数,有些年份是闰年,我不知道该怎么做.任何帮助将非常感激.我的代码:
is there a way of organising a number of days calculated by working out the difference between two dates, into different sections e.g. for 364 days it would be: 0 years, 11 months, 30 days, hours, minutes etc. I thought using logical operators may work like % and / but as different months have different amounts of days and some years are leap years i'm not sure how to do it. Any help would be much appreciated. My code:
import java.util.*;
public class CleanDate {
public static void main(String[] args) {
Calendar cDate = GregorianCalendar.getInstance();
cDate.set(2011, 0, 31, 00, 00, 00);
Date date1 = cDate.getTime();
Date date2 = new Date();
Calendar calendar1 = Calendar.getInstance();
Calendar calendar2 = Calendar.getInstance();
calendar1.setTime(date1);
calendar2.setTime(date2);
long milliseconds1 = calendar1.getTimeInMillis();
long milliseconds2 = calendar2.getTimeInMillis();
long diff = milliseconds2 - milliseconds1;
long diffSeconds = diff / 1000;
long diffMinutes = diff / (60 * 1000);
long diffHours = diff / (60 * 60 * 1000);
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.println("Time in minutes: " + diffMinutes + " minutes.");
System.out.println("Time in hours: " + diffHours + " hours.");
System.out.println("Time in days: " + diffDays + " days.");
}
}
推荐答案
你可以像这样有效地使用 Joda Time:Interval
允许获取两个日期之间的时间间隔.
You could effectively use Joda Time like this:
Interval
allows to get time interval between two dates.
DateTime end = new DateTime(2006, 1, 1, 0, 0, 0, 0);
Interval interval = new Interval(start, end);
Period period = interval.toPeriod();
System.out.println(period.getYears()+" years, "
period.getMonths()+" months, "+period.getWeeks()+" weeks, "+period.getDays()+", days");
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