问题描述

Java DateTimeFormatter 当您尝试超出可能范围的日期时抛出异常，例如:

Java DateTimeFormatter throws an exception for when you try a date that goes outside of a possible range, for example:

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("M/d/yyyy");
String dateString = "12/32/2015";
LocalDate ld = LocalDate.parse(dateString, dtf);

将抛出:

Exception in thread "main" java.time.format.DateTimeParseException: Text '12/32/2015' could not be parsed: Invalid value for DayOfMonth (valid values 1 - 28/31): 32

但是当我输入一个无效的日历日期，根据他们的标准，它在语法上仍然是可能的，它会自动将其更正为有效日期，例如:

But when I enter an invalid calendar date that is still syntactically possible by their standards, it autocorrects it to be a valid date, for example:

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("M/d/yyyy");
String dateString = "2/31/2015";
LocalDate ld = LocalDate.parse(dateString, dtf);

它成功解析但自动更正为 2015-02-28.我不希望这种行为，我希望它在日期不是有效的日历日期时仍然抛出异常.有没有我可以设置的内置选项来实现这一点，还是我真的必须尝试手动筛选出这些实例?

it successfully parses but autocorrects to 2015-02-28. I don't want this behavior, I want it to still throw an exception when the date is not a valid calendar date. Is there a built-in option I can set for that to happen, or do I really have to try to manually sift out these instances?

推荐答案

您可以使用 STRICT 解析器样式:

You can use a STRICT resolver style:

import static java.time.format.ResolverStyle.STRICT;

DateTimeFormatter dtf = DateTimeFormatter.ofPattern("M/d/uuuu").withResolverStyle(STRICT);

默认情况下，ofPattern 使用 一种 SMART 解析器样式，它将使用合理的默认值.

By default, ofPattern uses a SMART resolver style which will use reasonable defaults.

请注意，我使用的是 uuuu 而不是 yyyy，即 YEAR 而不是 YEAR_OF_ERA.假设您使用的是公历系统，则两者在当前时代(第 1 年或更大)中的年数相等.上面的链接中更详细地解释了差异.

Note that I have used uuuu instead of yyyy, i.e. YEAR instead of YEAR_OF_ERA. Assuming you are in a Gregorian calendar system, the two are equivalent for years in the current era (year 1 or greater). The difference is explained in more details in the links above.

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