问题描述
我正在使用 Mockito 1.9.0.我想在 JUnit 测试中模拟一个类的单个方法的行为，所以我有
I'm using Mockito 1.9.0. I want mock the behaviour for a single method of a class in a JUnit test, so I have
final MyClass myClassSpy = Mockito.spy(myInstance);
Mockito.when(myClassSpy.method1()).thenReturn(myResults);
问题是，在第二行中，myClassSpy.method1() 实际上被调用，导致异常.我使用模拟的唯一原因是以后，每当调用 myClassSpy.method1() 时，不会调用真正的方法，而 myResults 对象将是回.
The problem is, in the second line, myClassSpy.method1() is actually getting called, resulting in an exception. The only reason I'm using mocks is so that later, whenever myClassSpy.method1() is called, the real method won't be called and the myResults object will be returned.
MyClass 是一个接口，而 myInstance 是一个实现，如果这很重要的话.
MyClass is an interface and myInstance is an implementation of that, if that matters.
我需要做些什么来纠正这种间谍行为?
What do I need to do to correct this spying behaviour?
推荐答案
让我引用 官方文档:
有时不可能使用 when(Object) 来存根间谍.示例:
Important gotcha on spying real objects!
Sometimes it's impossible to use when(Object) for stubbing spies. Example:
List list = new LinkedList();
List spy = spy(list);
// Impossible: real method is called so spy.get(0) throws IndexOutOfBoundsException (the list is yet empty)
when(spy.get(0)).thenReturn("foo");
// You have to use doReturn() for stubbing
doReturn("foo").when(spy).get(0);
在你的情况下，它是这样的:
In your case it goes something like:
doReturn(resultsIWant).when(myClassSpy).method1();
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