问题描述

我一直在寻找将时间从 GMT 转换为本地时间的最简单方法.当然，要考虑正确的 DST 日期并尽可能标准.

I was looking for the simplest way to convert a date an time from GMT to my local time. Of course, having the proper DST dates considered and as standard as possible.

我能想到的最直接的代码是:

The most straight forward code I could come up with was:

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String inpt = "2011-23-03 16:40:44";
Date inptdate = null;
try {
    inptdate = sdf.parse(inpt);
} catch (ParseException e) {e.printStackTrace();}   
Calendar tgmt = new GregorianCalendar(TimeZone.getTimeZone("GMT"));
tgmt.setTime(inptdate);

Calendar tmad = new GregorianCalendar(TimeZone.getTimeZone("Europe/Madrid"));
tmad.setTime(inptdate);

System.out.println("GMT:		" + sdf.format(tgmt.getTime()));
System.out.println("Europe/Madrid:	" + sdf.format(tmad.getTime()));

但我认为我没有正确理解 getTime 将返回的内容.

But I think I didn't get the right concept for what getTime will return.

推荐答案

这里的问题是 DateFormat 类有一个时区.试试这个例子:

The catch here is that the DateFormat class has a timezone. Try this example instead:

    SimpleDateFormat sdfgmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
    sdfgmt.setTimeZone(TimeZone.getTimeZone("GMT"));

    SimpleDateFormat sdfmad = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
    sdfmad.setTimeZone(TimeZone.getTimeZone("Europe/Madrid"));

    String inpt = "2011-23-03 16:40:44";
    Date inptdate = null;
    try {
        inptdate = sdfgmt.parse(inpt);
    } catch (ParseException e) {e.printStackTrace();}

    System.out.println("GMT:		" + sdfgmt.format(inptdate));
    System.out.println("Europe/Madrid:	" + sdfmad.format(inptdate));

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