问题描述
Set
为什么不提供一个操作来获取一个等于另一个元素的元素?
Why doesn't Set
provide an operation to get an element that equals another element?
Set<Foo> set = ...;
...
Foo foo = new Foo(1, 2, 3);
Foo bar = set.get(foo); // get the Foo element from the Set that equals foo
我可以问 Set
是否包含一个等于 bar
的元素,那为什么我不能得到那个元素呢?:(
I can ask whether the Set
contains an element equal to bar
, so why can't I get that element? :(
为了澄清,equals
方法被覆盖,但它只检查其中一个字段,而不是全部.所以两个被认为相等的 Foo
对象实际上可以有不同的值,这就是为什么我不能只使用 foo
.
To clarify, the equals
method is overridden, but it only checks one of the fields, not all. So two Foo
objects that are considered equal can actually have different values, that's why I can't just use foo
.
推荐答案
如果元素相等,那么获取元素就没有意义了.Map
更适合这个用例.
There would be no point of getting the element if it is equal. A Map
is better suited for this usecase.
如果你仍然想找到元素,你别无选择,只能使用迭代器:
If you still want to find the element you have no other option but to use the iterator:
public static void main(String[] args) {
Set<Foo> set = new HashSet<Foo>();
set.add(new Foo("Hello"));
for (Iterator<Foo> it = set.iterator(); it.hasNext(); ) {
Foo f = it.next();
if (f.equals(new Foo("Hello")))
System.out.println("foo found");
}
}
static class Foo {
String string;
Foo(String string) {
this.string = string;
}
@Override
public int hashCode() {
return string.hashCode();
}
@Override
public boolean equals(Object obj) {
return string.equals(((Foo) obj).string);
}
}
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