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        Spring Data Mongo:如何按其字段返回嵌套对象?

        Spring Data Mongo: How to return nested object by its field?(Spring Data Mongo:如何按其字段返回嵌套对象?)
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                  本文介绍了Spring Data Mongo:如何按其字段返回嵌套对象?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我有域名:

                  class Company {
                      List<Job> jobs;
                  }
                  

                  有没有办法从集合中返回嵌套对象:

                  Is there a way to return nested object from collection like:

                  @Repository
                  public interface CompanyRepository extends MongoRepository<Company, String>{
                      Job findByJobId(String jobId);
                  }
                  

                  推荐答案

                  我必须对你的 Job 模型的结构做一些假设,但是假设是这样的:

                  I have to make some assumptions about the structure of your Job model, but assuming something like this:

                  public class Job {
                      private String id;
                      // other attributes and methods
                  }
                  

                  ... 并假设此模型嵌入在您的 Company 模型中,而不是在另一个集合中表示,您将不得不通过 MongoTemplate 路径进行自定义实现.Spring Data 查询 API 将无法弄清楚如何获取您想要的内容,因此您必须自己实现该方法.

                  ... and assuming that this model is embedded in your Company model, and not represented in another collection, you will have to go the custom implementation via MongoTemplate route. The Spring Data query API is not going to be able to figure out how to get what you want, so you must implement the method yourself.

                  @Repository
                  public interface CompanyRepository extends CompanyOperations, MongoRepository<Company, String>{
                  } 
                  
                  public interface CompanyOperations {
                      Job findByJobId(String jobId);
                  }
                  
                  public class CompanyRepositoryImpl implements CompanyOperations {
                      @Autowired private MongoTemplate mongoTemplate;
                  
                      @Override
                      public Job findByJobId(String jobId){
                          Company company = mongoTemplate.findOne(new Query(Criteria.where("jobs.id").is(jobId)), Company.class);
                          return company.getJobById(jobId); //implement this method in `Company` and save yourself some trouble.
                      }
                  }
                  

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