问题描述
我正在向 UIWebView 发送请求.加载的网页上有 AJAX 调用.我需要分析 AJAX 流量以确定用户是否登录.为此,我在 AppDelegate 中安装了一个 NSURLCache:
I am sending a request to a UIWebView. There are AJAX-calls on the loaded webpage. I need to analyze the AJAX-traffic in order to determinate, if the user is logged in or not. For doing this I installed a NSURLCache in the AppDelegate:
MYURLCache *cache = [[MYURLCache alloc] init];
[NSURLCache setSharedURLCache:cache];
这个 MYURLCache 类正确接收通过 webview 运行的流量.我只能终止 AJAX 调用.然后我产生一个自己的 AJAX 调用请求.这个返回来自网络服务器的完美响应.所以现在要做的最后一步是构造 NSCachedURLResponse 返回对象.我也管理了这个,但是 webview 在返回对象时根本不做任何事情.如果我只返回 nil,WebView 加载一切正常(nil 是 NSURLCache 的消息,没有缓存,所以 webview 应该开始自己加载它).
This MYURLCache-class correctly receives the traffic that runs through the webview. I can terminate the AJAX-calls only. I then spawn an own request of the AJAX-calls. This one returns the perfectly fine response from the webserver. So the last step to do now is constructing the NSCachedURLResponse return object. I also managed this, but the webview simply does nothing when returning the objects. If I return just nil, the WebView loads everything fine (nil is the message for the NSURLCache, that nothing is cached, so the webview should start to load it on its own).
- (NSCachedURLResponse *)cachedResponseForRequest:(NSURLRequest *)request {
if ([[[request URL] absoluteString] rangeOfString:@"/ajax/"].location == NSNotFound) {
return nil;
} else {
ASIHTTPRequest *asirequest = [ASIHTTPRequest requestWithURL:[request URL]];
[asirequest setValidatesSecureCertificate:NO];
[asirequest startSynchronous];
NSError *error = [asirequest error];
NSData* data = [[asirequest responseString] dataUsingEncoding:NSUTF8StringEncoding];
// Create the cacheable response
NSURLResponse *urlresponse = [[NSURLResponse alloc] initWithURL:[request URL] MIMEType:@"application/json" expectedContentLength:[data length] textEncodingName:@"UTF-8"];
NSCachedURLResponse *cachedResponse = [[NSCachedURLResponse alloc] initWithResponse:urlresponse data:data];
NSLog(@"cachedResponse %@", cachedResponse);
NSLog(@"cachedResponse data %@", [[NSString alloc] initWithData:[cachedResponse data] encoding:NSUTF8StringEncoding]);
return cachedResponse;
}
return nil;
}
推荐答案
我找到了解决这个问题的方法...我认为这与缺少的标题有关.
I found one solution to this problem... I think it has got something to do with the headers that were missing.
如果我替换
NSURLResponse *urlresponse = [[NSURLResponse alloc] initWithURL:[request URL] MIMEType:@"application/json" expectedContentLength:[data length] textEncodingName:@"UTF-8"];
NSCachedURLResponse *cachedResponse = [[NSCachedURLResponse alloc] initWithResponse:urlresponse data:data];
有
NSHTTPURLResponse *urlresponse = [[NSHTTPURLResponse alloc] initWithURL:request.URL statusCode:200 HTTPVersion:@"1.1" headerFields:nil];
NSCachedURLResponse *cachedResponse = [[NSCachedURLResponse alloc] initWithResponse:urlresponse data:data];
整个事情都有效.该答案还建议了请求的附加自定义标头.https://stackoverflow.com/a/15234850/274518
The whole thing works. This answer in addition suggested the additional custom header of the request. https://stackoverflow.com/a/15234850/274518
NSDictionary *headers = @{@"Access-Control-Allow-Origin" : @"*", @"Access-Control-Allow-Headers" : @"Content-Type"};
NSHTTPURLResponse *urlresponse = [[NSHTTPURLResponse alloc] initWithURL:request.URL statusCode:200 HTTPVersion:@"1.1" headerFields:headers];
就我而言,我不需要它.
In my case I did not needed it.
这篇关于NSCachedURLResponse 返回对象,但 UIWebView 不解释内容的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!