本文介绍了目标 - C:从 URL 加载图像?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
Sorry for question title. I can not find a suitable title.
I have UITableView
content images from url when i open the UITableView
the View did not show until the images loaded and that takes along time.
I get the images from JSON by php.
I want to show the table and then images loading process.
This is code from my app:
NSDictionary *info = [json objectAtIndex:indexPath.row];
cell.lbl.text = [info objectForKey:@"title"];
NSString *imageUrl = [info objectForKey:@"image"];
cell.img.image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:imageUrl]]];
[cell.img.layer setBorderColor: [[UIColor blackColor] CGColor]];
[cell.img.layer setBorderWidth: 1.0];
return cell;
Sorry my english is weak.
解决方案
Perform the web request on a separate thread, to not block the UI. Here is an example using NSOperation
. Remember to only update the UI on the main thread, as shown with performSelectorOnMainThread:
.
- (void)loadImage:(NSURL *)imageURL
{
NSOperationQueue *queue = [NSOperationQueue new];
NSInvocationOperation *operation = [[NSInvocationOperation alloc]
initWithTarget:self
selector:@selector(requestRemoteImage:)
object:imageURL];
[queue addOperation:operation];
}
- (void)requestRemoteImage:(NSURL *)imageURL
{
NSData *imageData = [[NSData alloc] initWithContentsOfURL:imageURL];
UIImage *image = [[UIImage alloc] initWithData:imageData];
[self performSelectorOnMainThread:@selector(placeImageInUI:) withObject:image waitUntilDone:YES];
}
- (void)placeImageInUI:(UIImage *)image
{
[_image setImage:image];
}
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