问题描述
我正在寻找某人来协助我在我的应用程序中所需的代码,以将图像从它们存储在 HTC 愿望作为标准(画廊)的位置复制到 SD 卡上的另一个文件夹.我希望用户能够单击一个按钮并将某个文件从 SD 卡库文件夹复制到 SD 卡上的另一个文件夹?谢谢
I am looking for someone to assist in the code i require in my application to copya image from where they get stored on the HTC desire as standard(the gallery) to a another folder on the SD card. I want the user to be able to click on a button and a certain file is copied from the SD card gallery folder to the another folder on the SD card? Thanks
推荐答案
Usmaan,
您可以通过以下方式启动图库选择器意图:
You can launch the gallery picker intent with the following:
public void imageFromGallery() {
Intent getImageFromGalleryIntent =
new Intent(Intent.ACTION_PICK, MediaStore.Images.Media.INTERNAL_CONTENT_URI);
startActivityForResult(getImageFromGalleryIntent, SELECT_IMAGE);
}
返回时,通过以下部分代码获取选中图片的路径:
When it returns, get the path of the selected image with the following portion of code:
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (resultCode == RESULT_OK) {
switch(requestCode) {
case SELECT_IMAGE:
mSelectedImagePath = getPath(data.getData());
break;
}
}
public String getPath(Uri uri) {
String[] projection = { MediaStore.Images.Media.DATA };
Cursor cursor = managedQuery(uri, projection, null, null, null);
startManagingCursor(cursor);
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
现在您已将路径名包含在字符串中,您可以将其复制到另一个位置.
Now that you have the pathname in a string you can copy it to another location.
干杯!
如果您只需要复制文件,请尝试...
If you just need to copy a file try something like...
try {
File sd = Environment.getExternalStorageDirectory();
File data = Environment.getDataDirectory();
if (sd.canWrite()) {
String sourceImagePath= "/path/to/source/file.jpg";
String destinationImagePath= "/path/to/destination/file.jpg";
File source= new File(data, sourceImagePath);
File destination= new File(sd, destinationImagePath);
if (source.exists()) {
FileChannel src = new FileInputStream(source).getChannel();
FileChannel dst = new FileOutputStream(destination).getChannel();
dst.transferFrom(src, 0, src.size());
src.close();
dst.close();
}
}
} catch (Exception e) {}
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