本文介绍了如何求和 N 次(HH:MM 格式)?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!
问题描述
我正在使用以下示例代码来计算两个不同时间值的总和.现在我想得到 N 个时间值的总和.
I am using the following sample code to calculate sum of two different time values. Now I want to get the sum of N number of time values.
// numbers for testing
$o="12:59";
$p="0:58";
// display for testing
echo "$o<br />";
echo "$p<br />";
echo AddPlayTime($o,$p);
// FUNCTION - ADD HOURS and MINUTES
function AddPlayTime ($oldPlayTime, $PlayTimeToAdd) {
$old=explode(":",$oldPlayTime);
$play=explode(":",$PlayTimeToAdd);
$hours=$old[0]+$play[0];
$minutes=$old[1]+$play[1];
if($minutes > 59){
$minutes=$minutes-60;
$hours++;
}
if($minutes < 10){
$minutes = "0".$minutes;
}
if($minutes == 0){
$minutes = "00";
}
$sum=$hours.":".$minutes;
return $sum;
}
推荐答案
这应该满足您的要求:
$times
是时间数组,你可以添加你想要的时间
$times
is the array of times and you can add how many time you want
$times = array();
$times[] = "12:59";
$times[] = "0:58";
$times[] = "0:02";
// pass the array to the function
echo AddPlayTime($times);
function AddPlayTime($times) {
$minutes = 0; //declare minutes either it gives Notice: Undefined variable
// loop throught all the times
foreach ($times as $time) {
list($hour, $minute) = explode(':', $time);
$minutes += $hour * 60;
$minutes += $minute;
}
$hours = floor($minutes / 60);
$minutes -= $hours * 60;
// returns the time already formatted
return sprintf('%02d:%02d', $hours, $minutes);
}
编辑
我用正确的变量名称编辑了代码.现在更正确了.
I edited the code with the right names of the variables. It is more correct now.
希望这有帮助:-)
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