问题描述

我有数据库表:images 和 category

目前唯一插入到类别表的函数是这样的:

Currently the only function to insert in category table is similar to this:

public function add($ttitle)
{      
try
    {
        $stmt = $this->db->prepare("INSERT INTO category (title) VALUES(:title)");
        $stmt->bindparam(":title",$ttitle);                 
        $stmt->execute();
        return true;

    }
    catch(PDOException $e)
    {
        echo $e->getMessage();  
        return false;
    }

}

我有一个表格可以输入标题和插入网址图片的可能性.

I have a form to enter title and the possibility of inserting urls images.

通过单击提交标题，我想转到类别表，到目前为止还可以，图像应该转到表图像，每个图像都有一个 id，但内部连接到类别的 id.

By clicking on the submit the title I want to go to the category table, so far ok, images should go to the table images, an id for each image but with inner join to the id of the category.

表格images:

id_image | category_id | dir_image

我无法正确执行此操作

$stmt = $this->db->prepare("INSERT INTO category (title) VALUES(:ttitle)");

$stmt = $this->db->prepare("SELECT id_image FROM images WHERE id_category = category_id ");

我想要的结果示例:

html 表单

Category title: Test
Image1:   image1.png
Image2:   image2.png
Image3:   image3.png
Image4:   image4.png
              Submit

提交后

表格类别:

 id_category | title
    1          Test

表格图片:

 id_image | category_id | dir_image
    1            1         image1.png
    2            1         image2.png
    3            1         image3.png
    4            1         image4.png

<小时>

更新:

public function add($ttitle,$images)
{
try {
        $stmt = $this->db->prepare("INSERT INTO category (title) VALUES(:title)");
        $stmt->bindparam(":title",$ttitle);                    
        $stmt->execute();

        $lastId = $db->lastInsertId();

       $imgs = count($images);
       for ($i = 0; $i < $imgs; $i++){

       $stmt = $this->db->prepare("INSERT INTO images (category_id, dir_image) VALUES (:title)");
        $stmt->bindparam(":category_id",$lastId); 
        $stmt->bindparam(":dir_image",$images);
        $stmt = $this->db->prepare($sql);
        $stmt->execute()

        } 



        return true;
    }
    catch(PDOException $e) {
        echo $e->getMessage();    
        return false;
    }

}

推荐答案

几件事:

1. 删除for循环中的第二个prepare语句
2. 在sql语句的VALUES()中添加绑定参数
3. 使用 for 循环迭代器或使用 foreach
索引 $images 数组

1. Remove the second prepare statement inside for loop
2. Add binded params into the VALUES() of sql statement
3. Index the $images array with for loop iterator or use foreach

查看调整后的for循环:

$stmt = $this->db->prepare("INSERT INTO images (category_id, dir_image) 
                            VALUES (:category_id, :dir_image)");

$stmt->bindParam(":category_id" ,$lastId); 
$stmt->bindParam(":dir_image", $image);
for ($i = 0; $i < count($images); $i++){
    $image = $images[$i];
    $stmt->execute();
} 

或者使用 foreach 循环 (假设是一维数组):

$stmt = $this->db->prepare("INSERT INTO images (category_id, dir_image) 
                            VALUES (:category_id, :dir_image)");

$stmt->bindParam(":category_id", $lastId); 
$stmt->bindParam(":dir_image", $item);
foreach ($images as $item){
    $stmt->execute();
} 

这篇关于带 PDO 的多个刀片的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！