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        如何将具有相同索引和值的 2 个数组与 php 组合?

        How to combine 2 arrays that have the same index and value with php?(如何将具有相同索引和值的 2 个数组与 php 组合?)
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                • 本文介绍了如何将具有相同索引和值的 2 个数组与 php 组合?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我有 2 个数组,如下所示:

                  I have 2 array like follows:

                  $array1 = [
                   '0' => [
                     'no_invoice' => 'INV0001',
                     'product_code' => '1111111',
                    ], 
                   '1' => [
                    'no_invoice' => 'INV0001',
                    'product_code' => '1111112',
                   ]
                  ];
                  
                    $array2 = [
                      '0' => [
                        'product_code' => '1111112',
                        'free_valie' => 839,
                        'count' => 1240
                      ],
                    ];
                  

                  是否可以将上面的数组组合成这样:

                  Is it possible to combine arrays above to be like this:

                  Array(
                   [0] => Array
                    (
                      'no_invoice' => 'INV0001',
                      'product_code' => '1111111',
                    )
                   [1] => Array
                    (
                      'no_invoice' => 'INV0001',
                      'product_code' => '1111112',
                      'free_valie' => 839,
                      'count' => 1240
                    )
                  )
                  

                  所以,如果数组具有相同的产品代码,那么它将像上面的例子一样加入.

                  So, if array have same product code, then it will join like the example above.

                  我尝试过使用数组合并,array_merge($array1, $array2);但是结果是这样的:

                  I have been tried with use array merge, array_merge($array1, $array2); But the result is like this:

                  Array(
                   [0] => Array
                    (
                      'no_invoice' => 'INV0001',
                      'product_code' => '1111111',
                    )
                   [1] => Array
                    (
                      'no_invoice' => 'INV0001',
                      'product_code' => '1111112',
                    )
                   [2] => Array
                    (
                      'product_code' => '1111112',
                      'free_valie' => 839,
                      'count' => 1240
                    )
                  )
                  

                  推荐答案

                  此代码将满足您的需求.它使用 <遍历 $array1 中的每个值code>array_search 以查看条目的 product_code 是否也存在于 $array2 中(通过查看 product_code使用 array_column<提取的 $array2 列/代码>).如果是,则合并这些值.请注意,我们在 foreach 中使用了 &$val,导致值通过引用传递,从而允许在循环中修改它

                  This code will do what you want. It loops over each value in $array1, using array_search to see if the entrie's product_code is also present in $array2 (by looking through the product_code column of $array2 extracted using array_column). If it is, the values are merged. Note that we use &$val in the foreach, causing the value to be passed by reference which allows it to be modified in the loop

                  foreach ($array1 as &$val) {
                      if (($k = array_search($val['product_code'], array_column($array2, 'product_code'))) !== false) {
                          $val = array_merge($val, $array2[$k]);
                      }
                  }
                  
                  print_r($array1);
                  

                  输出:

                  Array
                  (
                      [0] => Array
                          (
                              [no_invoice] => INV0001
                              [product_code] => 1111111
                          )
                  
                      [1] => Array
                          (
                              [no_invoice] => INV0001
                              [product_code] => 1111112
                              [free_valie] => 839
                              [count] => 1240
                          )
                  
                  )
                  

                  3v4l.org 上的演示

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