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问题描述
我在 Pandas 数据框中有两列是日期.
I have two columns in a Pandas data frame that are dates.
我希望从另一列中减去一列,结果是天数的差异作为整数.
I am looking to subtract one column from another and the result being the difference in numbers of days as an integer.
查看数据:
df_test.head(10)
Out[20]:
First_Date Second Date
0 2016-02-09 2015-11-19
1 2016-01-06 2015-11-30
2 NaT 2015-12-04
3 2016-01-06 2015-12-08
4 NaT 2015-12-09
5 2016-01-07 2015-12-11
6 NaT 2015-12-12
7 NaT 2015-12-14
8 2016-01-06 2015-12-14
9 NaT 2015-12-15
我已经成功创建了一个新列,不同之处:
I have created a new column successfully with the difference:
df_test['Difference'] = df_test['First_Date'].sub(df_test['Second Date'], axis=0)
df_test.head()
Out[22]:
First_Date Second Date Difference
0 2016-02-09 2015-11-19 82 days
1 2016-01-06 2015-11-30 37 days
2 NaT 2015-12-04 NaT
3 2016-01-06 2015-12-08 29 days
4 NaT 2015-12-09 NaT
但是我无法获得结果的数字版本:
However I am unable to get a numeric version of the result:
df_test['Difference'] = df_test[['Difference']].apply(pd.to_numeric)
df_test.head()
Out[25]:
First_Date Second Date Difference
0 2016-02-09 2015-11-19 7.084800e+15
1 2016-01-06 2015-11-30 3.196800e+15
2 NaT 2015-12-04 NaN
3 2016-01-06 2015-12-08 2.505600e+15
4 NaT 2015-12-09 NaN
推荐答案
怎么样:
df_test['Difference'] = (df_test['First_Date'] - df_test['Second Date']).dt.days
如果没有缺失值(NaT
),这将返回差异为 int
,如果有,则返回 float
.
This will return difference as int
if there are no missing values(NaT
) and float
if there is.
Pandas 有关于 时间序列/日期功能 和 时间增量
Pandas have a rich documentation on Time series / date functionality and Time deltas
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