问题描述

我的小示例应用程序的输出如下:

The output I'm getting for my little example app is the following:

Welcome to the Calculator!
Please choose what you'd like to do:
0: Addition
1: Subtraction
2: Multiplication
3: Division
4: Quit Application
0
Enter your first number: 1
Enter your second number: 1
Your result is:
11

这是因为 add() 方法将 input() 作为字符串而不是数字.如何将它们用作数字?

This is because the addition() method is taking the input() as strings and not numbers. How can I use them as numbers?

这是我的整个脚本:

def addition(a, b):
    return a + b

def subtraction(a, b):
    return a - b

def multiplication(a, b):
    return a * b

def division(a, b):
    return a / b

keepProgramRunning = True

print "Welcome to the Calculator!"

while keepProgramRunning:    
    print "Please choose what you'd like to do:"

    print "0: Addition"
    print "1: Subtraction"
    print "2: Multiplication"
    print "3: Division"
    print "4: Quit Application"



    #Capture the menu choice.
    choice = raw_input()    

    if choice == "0":
        numberA = raw_input("Enter your first number: ")
        numberB = raw_input("Enter your second number: ")
        print "Your result is:"
        print addition(numberA, numberB)
    elif choice == "1":
        numberA = raw_input("Enter your first number: ")
        numberB = raw_input("Enter your second number: ")
        print "Your result is:"
        print subtraction(numberA, numberB)
    elif choice == "2":
        numberA = raw_input("Enter your first number: ")
        numberB = raw_input("Enter your second number: ")
        print "Your result is:"
        print multiplication(numberA, numberB)
    elif choice == "3":
        numberA = raw_input("Enter your first number: ")
        numberB = raw_input("Enter your second number: ")
        print "Your result is:"
        print division(numberA, numberB)
    elif choice == "4":
        print "Bye!"
        keepProgramRunning = False
    else:
        print "Please choose a valid option."
        print "
"

推荐答案

由于您正在编写一个可能也接受浮点数(1.5, 0.03)的计算器，因此更可靠的方法是使用这个简单的辅助函数:

Since you're writing a calculator that would presumably also accept floats (1.5, 0.03), a more robust way would be to use this simple helper function:

def convertStr(s):
    """Convert string to either int or float."""
    try:
        ret = int(s)
    except ValueError:
        #Try float.
        ret = float(s)
    return ret

这样，如果 int 转换不起作用，您将返回一个浮点数.

That way if the int conversion doesn't work, you'll get a float returned.

如果您不完全了解 python 2.x 如何处理整数除法.

简而言之，如果您希望 10/2 等于 2.5 而 不 2，您将需要执行 from __future__ import division 或将一个或两个参数转换为 float，如下所示:

In short, if you want 10/2 to equal 2.5 and not 2, you'll need to do from __future__ import division or cast one or both of the arguments to float, like so:

def division(a, b):
    return float(a) / float(b)

这篇关于如何在 Python 中将字符串转换为 int?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！