I know that i can do set from some_data then make it list, crop it and then make it set again.

set(list(set(some_data))[:5])  # don't look so friendly

我知道我在 set 中没有 __getitem__ 方法，这不会使整个切片成为可能，但如果有机会让它看起来更好?

I understand that i don't have __getitem__ method in set which wouldn't make the whole slice thing possible, but if there is a chance to make it look better?

我完全理解 set 是无序的.因此，最终 set 中会出现哪些元素并不重要.

And i completely understand that set is unordered. So it don't matter which elements will get in final set.

可能的选择是使用:

• 有序集

• 使用 dict 和 None 值:

set(dict(map(lambda x: (x, None), some_data)).keys()[:2])  # not that great

推荐答案

集合是可迭代的.如果您真的不在乎选择了您的集合中的哪些项目，您可以使用 itertools.islice 来获取一个迭代器，该迭代器将产生指定数量的项目(无论哪个在迭代顺序中排在第一位).将迭代器传递给 set 构造函数，您就可以在不使用任何额外列表的情况下获得子集:

Sets are iterable. If you really don't care which items from your set are selected, you can use itertools.islice to get an iterator that will yield a specified number of items (whichever ones come first in the iteration order). Pass the iterator to the set constructor and you've got your subset without using any extra lists:

import itertools

some_data = [1, 2, 4, 1, 6, 23, 3, 56, 6, 2, 3, 5, 6, 32, 2, 12, 5, 3, 2]
big_set = set(some_data)
small_set = set(itertools.islice(big_set, 5))

虽然这是您所要求的，但我不确定您是否真的应该使用它.集合可能会以非常确定的顺序进行迭代，因此如果您的数据经常包含许多相似的值，那么每次执行此操作时您最终可能会选择一个非常相似的子集.当数据由整数组成时(如示例中所示)，这尤其糟糕，这些整数对自身进行哈希处理.迭代集合时，连续的整数会经常按顺序出现.使用上面的代码，在 big_set 中只有 32 乱序(使用 Python 3.5)，所以 small_set 是 {32, 1, 2, 3, 4}.如果您将 0 添加到数据中，即使数据集变得很大，您几乎总是会以 {0, 1, 2, 3, 4} 结束，因为这些值将始终填满集合哈希表中的前五个位置.

While this is what you've asked for, I'm not sure you should really use it. Sets may iterate in a very deterministic order, so if your data often contains many similar values, you may end up selecting a very similar subset every time you do this. This is especially bad when the data consists of integers (as in the example), which hash to themselves. Consecutive integers will very frequently appear in order when iterating a set. With the code above, only 32 is out of order in big_set (using Python 3.5), so small_set is {32, 1, 2, 3, 4}. If you added 0 to the your data, you'd almost always end up with {0, 1, 2, 3, 4} even if the dataset grew huge, since those values will always fill up the first fives slots in the set's hash table.

为了避免这种确定性采样，您可以使用 random.sample 如 jprockbelly 建议的那样.

To avoid such deterministic sampling, you can use random.sample as suggested by jprockbelly.

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