问题描述
我需要解析一个 xml 文件来提取一些数据.我只需要一些具有某些属性的元素,这里是一个文档示例:
I need to parse a xml file to extract some data. I only need some elements with certain attributes, here's an example of document:
<root>
<articles>
<article type="news">
<content>some text</content>
</article>
<article type="info">
<content>some text</content>
</article>
<article type="news">
<content>some text</content>
</article>
</articles>
</root>
在这里,我只想获取类型为新闻"的文章.使用 lxml 最有效和最优雅的方法是什么?
Here I would like to get only the article with the type "news". What's the most efficient and elegant way to do it with lxml?
我尝试了 find 方法,但不是很好:
I tried with the find method but it's not very nice:
from lxml import etree
f = etree.parse("myfile")
root = f.getroot()
articles = root.getchildren()[0]
article_list = articles.findall('article')
for article in article_list:
if "type" in article.keys():
if article.attrib['type'] == 'news':
content = article.find('content')
content = content.text
推荐答案
你可以使用xpath,例如root.xpath("//article[@type='news']")
You can use xpath, e.g. root.xpath("//article[@type='news']")
此 xpath 表达式将返回所有 <article/>
元素的列表,该元素的type"属性值为news".然后,您可以对其进行迭代以执行您想要的操作,或者将其传递到任何地方.
This xpath expression will return a list of all <article/>
elements with "type" attributes with value "news". You can then iterate over it to do what you want, or pass it wherever.
要获取文本内容,您可以像这样扩展 xpath:
To get just the text content, you can extend the xpath like so:
root = etree.fromstring("""
<root>
<articles>
<article type="news">
<content>some text</content>
</article>
<article type="info">
<content>some text</content>
</article>
<article type="news">
<content>some text</content>
</article>
</articles>
</root>
""")
print root.xpath("//article[@type='news']/content/text()")
这将输出 ['some text', 'some text']
.或者,如果您只想要内容元素,则可以是 "//article[@type='news']/content"
-- 以此类推.
and this will output ['some text', 'some text']
. Or if you just wanted the content elements, it would be "//article[@type='news']/content"
-- and so on.
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