问题描述
我正在尝试在保存新模型实例时向用户发送电子邮件,并且我希望电子邮件包含指向该模型实例管理页面的链接.有没有办法获得正确的网址?我认为 Django 必须将这些信息存储在某个地方.
I'm trying to send an email to a user when a new model instance is saved and I want the email to include a link to the admin page for that model instance. Is there a way to get the correct URL? I figure Django must have that information stored somewhere.
推荐答案
这个 Django 片段 应该做:
from django.urls import reverse
from django.contrib.contenttypes.models import ContentType
from django.db import models
class MyModel(models.Model):
def get_admin_url(self):
content_type = ContentType.objects.get_for_model(self.__class__)
return reverse("admin:%s_%s_change" % (content_type.app_label, content_type.model), args=(self.id,))
self
引用父模型类,即self.id
引用对象的实例id
.您也可以将其设置为 property
通过将 @property
装饰器粘贴在方法签名之上来建模.
The self
refers to the parent model class, i.e. self.id
refers to the object's instance id
. You can also set it as a property
on the model by sticking the @property
decorator on top of the method signature.
Chris Pratt 下面 的答案在 ContentType
表.我的回答仍然有效",并且较少依赖于 Django 模型 instance._meta
内部.仅供参考.
The answer by Chris Pratt below saves a DB query over the ContentType
table. My answer still "works", and is less dependent on the Django model instance._meta
internals. FYI.
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