本文介绍了在python中制作一定范围内的均匀间隔数字列表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！
问题描述
What is a pythonic way of making list of arbitrary length containing evenly spaced numbers (not just whole integers) between given bounds? For instance:
my_func(0,5,10) # ( lower_bound , upper_bound , length )
# [ 0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5 ]
Note the Range() function only deals with integers. And this:
def my_func(low,up,leng):
list = []
step = (up - low) / float(leng)
for i in range(leng):
list.append(low)
low = low + step
return list
seems too complicated. Any ideas?
解决方案
Given numpy, you could use linspace:
Including the right endpoint (5):
In [46]: import numpy as np
In [47]: np.linspace(0,5,10)
Out[47]:
array([ 0. , 0.55555556, 1.11111111, 1.66666667, 2.22222222,
2.77777778, 3.33333333, 3.88888889, 4.44444444, 5. ])
Excluding the right endpoint:
In [48]: np.linspace(0,5,10,endpoint=False)
Out[48]: array([ 0. , 0.5, 1. , 1.5, 2. , 2.5, 3. , 3.5, 4. , 4.5])
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