问题描述
我想要一个长列表，例如 [1,2,3,4,5,15,16,17,18,19].为了初始化它，我尝试输入:
I want one long list, say [1,2,3,4,5,15,16,17,18,19] as an example. To initialize this, I try typing:
new_list = [range(1,6),range(15,20)]
但是这并没有做我想要的，返回:
However this doesn't do what I want, returning:
[[1, 2, 3, 4, 5], [15, 16, 17, 18, 19]]
当我这样做时:
len(new_list)
它返回 2，而不是我想要的 10 个元素(因为它在列表中创建了 2 个列表).显然，在这个例子中，我可以只输入我想要的内容，但我正在尝试对一些奇怪的迭代列表执行此操作，例如:
It returns 2, instead of the 10 elements I wanted (since it made 2 lists inside the list). Obviously in this example I could just type out what I want, but I'm trying to do this for some odd iterated lists that go like:
new_list = [range(101,6284),8001,8003,8010,range(10000,12322)]
需要一维列表而不是列表列表(或任何最好的名称).我猜这真的很容易而且我很想念它，但是经过相当多的搜索后，我没有想出任何有用的东西.有什么想法吗?
Desiring a 1-D list instead of a list of lists (or whatever it's best called). I'm guessing this is really easy and I'm missing it, but after quite a bit of searching I've come up with nothing too useful. Any ideas?
推荐答案
在 Python 2.x 上试试这个:
Try this for Python 2.x:
range(1,6) + range(15,20)
或者如果你使用的是 Python3.x，试试这个:
Or if you're using Python3.x, try this:
list(range(1,6)) + list(range(15,20))
用于处理中间元素，对于 Python 2.x:
For dealing with elements in-between, for Python 2.x:
range(101,6284) + [8001,8003,8010] + range(10000,12322)
最后是处理中间元素，对于 Python 3.x:
And finally for dealing with elements in-between, for Python 3.x:
list(range(101,6284)) + [8001,8003,8010] + list(range(10000,12322))
这里要记住的关键方面是，在 Python 2.x 中 range 返回一个列表，而在 Python 3.x 中它返回一个可迭代对象(因此需要将其显式转换为列表).对于将列表附加在一起，您可以使用 + 运算符.
The key aspects to remember here is that in Python 2.x range returns a list and in Python 3.x it returns an iterable (so it needs to be explicitly converted to a list). And that for appending together lists, you can use the + operator.
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