问题描述
我最近迁移到 Py 3.5.此代码在 Python 2.7 中正常工作:
I've very recently migrated to Py 3.5. This code was working properly in Python 2.7:
with open(fname, 'rb') as f:
lines = [x.strip() for x in f.readlines()]
for line in lines:
tmp = line.strip().lower()
if 'some-pattern' in tmp: continue
# ... code
升级到 3.5 后，我得到了:
After upgrading to 3.5, I'm getting the:
TypeError: a bytes-like object is required, not 'str'
最后一行出错(模式搜索代码).
error on the last line (the pattern search code).
我尝试在语句的任一侧使用 .decode() 函数，也尝试过:
I've tried using the .decode() function on either side of the statement, also tried:
if tmp.find('some-pattern') != -1: continue
-无济于事.
我能够快速解决几乎所有 2:3 的问题，但这个小声明让我很烦.
I was able to resolve almost all 2:3 issues quickly, but this little statement is bugging me.
推荐答案
你以二进制模式打开了文件:
You opened the file in binary mode:
with open(fname, 'rb') as f:
这意味着从文件中读取的所有数据都返回为 bytes 对象，而不是 str.然后你不能在包含测试中使用字符串:
This means that all data read from the file is returned as bytes objects, not str. You cannot then use a string in a containment test:
if 'some-pattern' in tmp: continue
您必须使用 bytes 对象来针对 tmp 进行测试:
You'd have to use a bytes object to test against tmp instead:
if b'some-pattern' in tmp: continue
或将文件作为文本文件打开，方法是将 'rb' 模式替换为 'r'.
or open the file as a textfile instead by replacing the 'rb' mode with 'r'.
这篇关于TypeError:在 Python3 中写入文件时需要一个类似字节的对象，而不是“str"的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！