问题描述
我有一个 Python 脚本，它以整数列表作为输入，我需要一次处理四个整数.不幸的是，我无法控制输入，否则我会将其作为四元素元组列表传入.目前，我正在以这种方式对其进行迭代:
I have a Python script which takes as input a list of integers, which I need to work with four integers at a time. Unfortunately, I don't have control of the input, or I'd have it passed in as a list of four-element tuples. Currently, I'm iterating over it this way:
for i in range(0, len(ints), 4):
# dummy op for example code
foo += ints[i] * ints[i + 1] + ints[i + 2] * ints[i + 3]
不过，它看起来很像C-think"，这让我怀疑有一种更 Python 的方式来处理这种情况.该列表在迭代后被丢弃，因此不需要保留.也许这样的事情会更好?
It looks a lot like "C-think", though, which makes me suspect there's a more pythonic way of dealing with this situation. The list is discarded after iterating, so it needn't be preserved. Perhaps something like this would be better?
while ints:
foo += ints[0] * ints[1] + ints[2] * ints[3]
ints[0:4] = []
还是不太感觉"对，不过.:-/
Still doesn't quite "feel" right, though. :-/
相关问题:怎么做你在 Python 中将列表分成大小均匀的块?
推荐答案
修改自itertools 文档的 >Recipes 部分:
from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
args = [iter(iterable)] * n
return zip_longest(*args, fillvalue=fillvalue)
示例
grouper('ABCDEFG', 3, 'x') # --> 'ABC' 'DEF' 'Gxx'
注意:在 Python 2 上使用 izip_longest 而不是 zip_longest.
Note: on Python 2 use izip_longest instead of zip_longest.
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