问题描述
我正在使用 Leafletjs 在 openstretmap 上显示一些多边形.
I'm using leafletjs to display some polygons on an openstretmap.
我有一个外部数据资源,它为我提供了多边形的坐标.不幸的是,这个数组的坐标顺序错误.
I have an external data ressource which gives me the coordinates for the polygons. Unfortunately this array has the wrong order for the coordinates.
示例:我明白了:
[[10.5254913,52.2734311],[10.5258872,52.2734632]]
[[10.5254913,52.2734311],[10.5258872,52.2734632]]
我需要:
[[52.2734311,10.5254913],[52.2734632,10.5258872]]
[[52.2734311,10.5254913],[52.2734632,10.5258872]]
所以我给自己写了一个小函数,它遍历数组并反转条目:
So I wrote myself a little function which iterates through the array and reverses the entries:
var polCoords = [];
$.each(value.polygon[0], function(key,value){
polCoords[key] = [value[1],value[0]];
});
这很好用.但是现在我发现多边形的一些数组是多维的!所以我有一个这样的数组:
This works just fine. But now I discovered that some arrays for the polygons are multidimensional! So I have an array like this:
[[[10.5261828,52.2726556],[10.5263222,52.2726767],[10.5263578,52.2726821],[10.5263637,52.2726677],[10.5263738,52.2726428],[10.5264042,52.2725678],[10.526186,52.2725346],[10.5261395,52.272649],[10.5261828,52.2726556]],[[10.5261828,52.2726556],[10.5261713,52.2726821],[10.5261621,52.2727047],[10.5259248,52.2726687],[10.5257879,52.2726479],[10.5257435,52.2727573],[10.5258014,52.2727661],[10.5257967,52.2727777],[10.5260173,52.2728113],[10.5261107,52.2728254],[10.5260641,52.2729403],[10.5259711,52.2729262],[10.5259526,52.2729234],[10.5258101,52.2732746],[10.5258697,52.2732837],[10.5260636,52.2733132],[10.5261371,52.2733243],[10.5262746,52.2729854],[10.5262888,52.2729876],[10.526312,52.2729304],[10.5262636,52.2729231],[10.5262239,52.272917],[10.5263222,52.2726767],[10.5261828,52.2726556]],[[10.5260636,52.2733132],[10.5260595,52.2733365],[10.5260575,52.2733486],[10.5258607,52.2733326],[10.5258631,52.2733195],[10.5258697,52.2732837],[10.5260636,52.2733132]]]
它似乎由多个多边形组成.
Which seems to consist of more than one polygon.
如何反转这个多维数组的每个条目?
How can I reverse every entry of this multidimensional array?
推荐答案
假设 array
是您的数据,尝试类似:
Assuming array
is your data, try something like:
var reversed = array.map(function reverse(item) {
return Array.isArray(item) && Array.isArray(item[0])
? item.map(reverse)
: item.reverse();
});
这是普通的 JavaScript.我认为在 jquery 中会是这样的:
This is vanilla JavaScript. I think in jquery would be something like:
var reversed = $.map(array, function reverse(item) {
return $.isArray(item) && $.isArray(item[0])
? $.map(item, reverse)
: item.reverse();
});
我没有尝试,但应该可以同时使用它们.告诉我.
I didn't try but should works both of them. Let me know.
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