问题描述

我正在使用 Gulp 将我的 sass 编译成 css.一个简单的任务编译 _/sass 目录中的 style.scss 文件，并将输出保存到项目的根目录中.style.scss 仅用于导入 _/sass 目录下的其他文件.

I'm using Gulp to compile my sass into css. A simple task compiles the style.scss file in the _/sass directory and saves the output into the root of the project. style.scss is used merely to import other files in the _/sass directory.

当我从命令行 ($ gulp) 运行默认任务时，我收到一个 sass 无法编译的错误.它全部包含在下面.我已从包含的文件中删除所有内容并再次运行该任务.我仍然收到相同的错误(我在网上阅读的内容表明这可能会测试编码问题.我不完全了解编码以及这可能会如何破坏我的场景).

When I run the default task from the command line ($ gulp) I get an error that the sass can't compile. It is included below in full. I have removed all content from the included files and run the task again. I still receive the same error (something I read online suggested this might test for an encoding issue. I don't fully understand encoding and how that might break things in my scenario).

我还从命令行 $ sass _/sass/style.scss style.css 运行，它与包含文件中的内容完美配合.这表明 gulp sass 插件本身存在问题.

I've also run from the command line $ sass _/sass/style.scss style.css which works perfectly with content in the included files. This suggests to me a problem with the gulp sass plugin itself.

来自 gulpfile.js 的相关片段:

The relevant snippets from gulpfile.js:

var gulp = require('gulp');
var sass = require('gulp-sass');

// Compile sass files
gulp.task('sass', function () {
    gulp.src('./_/sass/style.scss')
        .pipe(sass())
        .pipe(gulp.dest('./'));
});

// The default task (called when you run `gulp`)
gulp.task('default', function() {
  gulp.run('sass');

  // Watch files and run tasks if they change

  gulp.watch(['./_/sass/style.scss'], function() {
    gulp.run('sass');
  })
});

style.scss的全部内容:

The full contents of style.scss:

/* RESET */
@import '_/sass/reset';
/* TYPOGRAPHY */
@import '_/sass/typography';
/* MOBILE */
@import '_/sass/mobile';
/* MAIN */
@import '_/sass/main';

目录结构:

├── _
│ ├── inc
│ │ ├── stuff
│ ├── js
│ │ ├── otherstuff.js
│ └── sass
│     ├── main.scss
│     ├── mobile.scss
│     ├── print.scss
│     ├── reset.scss
│     ├── style.scss
│     └── typography.scss
├── gulpfile.js
└── style.css

终端吐出:

[gulp] Using file /Users/jeshuamaxey/project/dir/path/gulpfile.js
[gulp] Working directory changed to /Users/jeshuamaxey/project/dir/path/html5reset
[gulp] Running 'default'...
[gulp] Running 'sass'...
[gulp] Finished 'sass' in 3.18 ms
[gulp] Finished 'default' in 8.09 ms

stream.js:94
      throw er; // Unhandled stream error in pipe.
            ^
source string:11: error: file to import not found or unreadable: 'reset'

推荐答案

保持导入不变，只需在 gulp sass 模块中传递 includePaths 选项作为参数:

Keep your imports as is, just pass the includePaths option in your gulp sass module as an argument:

gulp.src('./_/sass/style.scss')
        .pipe(sass({ includePaths : ['_/sass/'] }))
        .pipe(gulp.dest('./'));

...应该为你做.

根据 https://github.com/dlmanning/gulp-sass/issues/1

这篇关于Gulp-sass 无法编译 scss 文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！