问题描述

我正在尝试在 for 循环中发出多个服务器请求.我发现 this question 并实施了建议的解决方案.但是它似乎不起作用.

I am trying to make several server requests inside a for loop. I found this question and implemented the suggested solution. However it doesn't seem to work.

    for (var i = 1; i <= 10; i++)
    {
    (function(i) {
    if(<some conditions>)
    {
    if (window.XMLHttpRequest) {
        // code for IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp[i]=new XMLHttpRequest();
      } else { // code for IE6, IE5
        xmlhttp[i]=new ActiveXObject("Microsoft.XMLHTTP");
      }
      xmlhttp[i].onreadystatechange=function() {
        if (xmlhttp[i].readyState==4 && xmlhttp[i].status==200) {
          document.getElementById("preselection").innerHTML=xmlhttp[i].responseText;
        }
      }
      xmlhttp[i].open("GET","getBuoys.php?q="+i,true);
      xmlhttp[i].send();
    }
})(i);
}

如果我删除 for 循环并将所有 xmlhttp[i] 更改为 xmlhttp，对于一个元素来说一切正常，但我无法发出多个请求.提前感谢您的任何建议.

If I remove the for loop and change all xmlhttp[i] to xmlhttp, everything works just fine for one element, but I can't make several requests. Thanks in advance for any suggestions.

推荐答案

试试下面的代码片段

// JavaScript
window.onload = function(){

    var f = (function(){
        var xhr = [], i;
        for(i = 0; i < 3; i++){ //for loop
            (function(i){
                xhr[i] = new XMLHttpRequest();
                url = "closure.php?data=" + i;
                xhr[i].open("GET", url, true);
                xhr[i].onreadystatechange = function(){
                    if (xhr[i].readyState === 4 && xhr[i].status === 200){
                        console.log('Response from request ' + i + ' [ ' + xhr[i].responseText + ']'); 
                    }
                };
                xhr[i].send();
            })(i);
        }
    })();

};

// PHP [closure.php]
echo "Hello Kitty -> " . $_GET["data"];

回应

Response from request 0 [ Hello Kitty -> 0]
Response from request 1 [ Hello Kitty -> 1]
Response from request 2 [ Hello Kitty -> 2] 

这篇关于循环中的 XMLHttpRequest的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！