问题描述

我正在尝试在 html 画布中绘制弯曲的箭头.我画一条曲线没有问题，但我不知道如何将 > 放在线的末尾(方向).

I'm trying to draw curved arrows in a html canvas. I have no problem to draw a curved line but I don't know how to put the > at the end of the line (direction).

ctx.beginPath();
  ctx.fillStyle = "rgba(55, 217, 56,"+ opacity +")";
  ctx.moveTo(this.fromX,this.fromY);
  ctx.quadraticCurveTo(this.controlX, this.controlY, this.toX, this.toY);
ctx.stroke();

我的想法是在最后的线的一小部分画一个三角形.如何获取直线中点的坐标?

My idea is taking a small part of the line at the end and draw a triangle. How can I get the coordinate of a point in the line?

下面是图片以便更好地理解.

Below is the image for better understanding.

推荐答案

由于您使用的是二次曲线，因此您知道两个点组成一条指向箭头方向"的直线:

Since you're using a quadratic curve, you know two points that make a line that points in the "direction" of your arrow head:

所以扔掉一点三角，你自己就有了解决方案.这是一个通用的函数，可以为你做这件事:

So throw down a smidge of trig and you have yourself a solution. Here's a generalized function that will do it for you:

http://jsfiddle.net/SguzM/

function drawArrowhead(locx, locy, angle, sizex, sizey) {
    var hx = sizex / 2;
    var hy = sizey / 2;

    ctx.translate((locx ), (locy));
    ctx.rotate(angle);
    ctx.translate(-hx,-hy);

    ctx.beginPath();
    ctx.moveTo(0,0);
    ctx.lineTo(0,1*sizey);    
    ctx.lineTo(1*sizex,1*hy);
    ctx.closePath();
    ctx.fill();

    ctx.translate(hx,hy);
    ctx.rotate(-angle);
    ctx.translate(-locx,-locy);
}        

// returns radians
function findAngle(sx, sy, ex, ey) {
    // make sx and sy at the zero point
    return Math.atan2((ey - sy), (ex - sx));
}

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