I created this DEMO from codepen.io

In this demo you can see :

<div class="photo-row">
<div class="photo-item">
<!--Posted image here <img src="image/abc.jpg"/>-->
</div>
</div>

This DEMO is working fine but. My question is how can I use my grid system like in this css:

<div class="photo">

        <div class="photo-row">
            <a href="#"><img src="abc.jpg"/></a>
        </div>
        <div class="photo-row">
            <a href="#"><img src="abc.jpg"/></a>
        </div>
</div>

I created second demo for this: second DEMO. In the second demo you can see the grid system not working like first DEMO.

Also my jQuery code:

(function($,sr){

  var debounce = function (func, threshold, execAsap) {
      var timeout;

      return function debounced () {
          var obj = this, args = arguments;
          function delayed () {
              if (!execAsap)
                  func.apply(obj, args);
              timeout = null;
          };

          if (timeout)
              clearTimeout(timeout);
          else if (execAsap)
              func.apply(obj, args);

          timeout = setTimeout(delayed, threshold || 100);
      };
  }
  // smartresize 
  jQuery.fn[sr] = function(fn){  return fn ? this.bind('resize', debounce(fn)) : this.trigger(sr); };

})(jQuery,'smartresize');

/* Wait for DOM to be ready */
$(function() {

    // Detect resize event
    $(window).smartresize(function () {
        // Set photo image size
        $('.photo-row').each(function () {
            var $pi    = $(this).find('.photo-item'),
                  cWidth = $(this).parent('.photo').width();

            // Generate array containing all image aspect ratios
            var ratios = $pi.map(function () {
                return $(this).find('img').data('org-width') / $(this).find('img').data('org-height');
            }).get();

            // Get sum of widths
            var sumRatios = 0, sumMargins = 0,
          minRatio  = Math.min.apply(Math, ratios);
            for (var i = 0; i < $pi.length; i++) {
                sumRatios += ratios[i]/minRatio;
            };

      $pi.each(function (){
        sumMargins += parseInt($(this).css('margin-left')) + parseInt($(this).css('margin-right'));
      });

            // Calculate dimensions
            $pi.each(function (i) {
                var minWidth = (cWidth - sumMargins)/sumRatios;
                $(this).find('img')
          .height(Math.floor(minWidth/minRatio))
                    .width(Math.floor(minWidth/minRatio) * ratios[i]);
            });
        });
    });
});

/* Wait for images to be loaded */
$(window).load(function () {

    // Store original image dimensions
    $('.photo-item img').each(function () {
      $(this)
        .data('org-width', $(this)[0].naturalWidth)
        .data('org-height', $(this)[0].naturalHeight);
    });

  $(window).resize();
});

Anyone can help me in this regard ? Thank you in advance for your answer.

Since you'll be creating the HTML dynamically you should remove the .photo-row container but keep .photo-item like so:

        <div class="photo-item">
            <a href="..."><img src="..." /></a>
        </div>
        <div class="photo-item">
            <a href="..."><img src="..." /></a>
        </div>
        <div class="photo-item">
            <a href="..."><img src="..." /></a>
        </div>
        ...

Then what you can do is wrap your elements with .photo-row on page load. First starting with various sets of two:

var imgGrab  = $('.photo-item'); //photos
var imgLength = imgGrab.length; //number of photos

for ( i=0; i<imgLength; i=i+3 ) {
   imgGrab.eq(i+1).add( imgGrab.eq(i+1) ).add( imgGrab.eq(i+2) ).wrapAll('<div class="photo-row"></div>'); //wrap photos
}

Then find the remanding ones and wrap those with .photo-row as well:

$(".photo-item").each(function(){
   if($(this).parent().is(":not(.photo-row)")){
     $(this).wrap('<div class="photo-row"></div>');
   }
});

This will wrap your images dynamically and let the CSS do its job regardless of the number of them:

CODEPEN

这篇关于jQuery 图像网格系统的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！