问题描述
有没有办法处理递归未知的确切数量的路由器参数?
Is there a way to handle recursively unknown exact number of router parameters?
例如:
我们有产品类别,其中可以有子类别,子类别可以有自己的子类别等等.有几个主要条件:
We have products categories, which can have subcategories, subcategories can have it's own subcategories and so on. There are a few main conditions:
- 如果此类类别没有子类别,我们将重定向到
/categories/{id}/items
,这将打开项目列表组件. - 如果类别有子类别,它应该被重定向到下一个嵌套树级别
/categories/{id}/{id}/.../{id}
这应该打开最后一个 categoryId 子类别列表组件. - 在到达最后一个没有子类别项目列表组件的类别后,将显示
/categories/{id}/{id}/.../{id}/items
.
- if a such category has no subcategories we redirect to
/categories/{id}/items
that will open items list component. - if category has subcategory it should be redirected to next nested tree level
/categories/{id}/{id}/.../{id}
which should open the last categoryId subcategories list component. - after getting to the last category which doesn't has subcategories items list component will be shown
/categories/{id}/{id}/.../{id}/items
.
检查和重定向的解决方案是使用路由器解析器.但是如何在路由模块中跟踪这些 url 呢?
The solutions to check and redirect is to have router resolver. But how track those urls in routing module ?
在我看来,路线应该是这样的:
From my perspective the routes should look something like this:
{
path: '/categories/:id',
component: SubcategoriesListComponent
},
{
path: '/categories/:id/**/:id',
component: SubcategoriesListComponent,
},
{
path: '/categories/:id/**/:id/items',
component: CategoryItemsListComponent
}
可以这样实现吗?
推荐答案
无组件路由的可能解决方案:在路线配置中
Possible solution with componentless routes: in routes config
{
path: 'categories/:id', children: [
{path: '**', component: SubcategoriesListComponent}
]
}
在组件文件中:
export class SubcategoriesListComponent {
constructor(aroute: ActivatedRoute) {
aroute.url.subscribe((data) => {
console.log('params ', data); //contains all the segments so put logic here of determining what to do according to nesting depth
});
}
}
这里是 输出示例(我在我的项目 ErrorComponent 上测试过,所以不要混淆)
Here is the output example (i tested on my project ErrorComponent so don't be confused)
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